Author Topic: What's wrong here? (Read 7818 times)

Sidoh · « **on:** February 07, 2006, 11:27:13 pm »

For those of you that are more mathematically inclined (*cough* MyndFyre/iago): please don't reply until the answer's been posted. Thanks!

deadly7 · « **Reply #1 on:** February 08, 2006, 12:38:19 am »

This should be in riddles, sorta.. Logic ~ Riddles, in a sense.
Since I know the answer (sidoh told me, I got semi close though) I can't post it.

Blaze · « **Reply #2 on:** February 08, 2006, 12:43:12 am »

[ROT13]
Gjb qbrfa'g rdhny bar..? V qba'g haqrefgnaq gur dhrfgvba irel jryy..
[/ROT13]

Sidoh · « **Reply #3 on:** February 08, 2006, 12:43:27 am »

I actually considered that, but I figured it was okay in General. It does make more sense here, so I moved it.

Quik · « **Reply #4 on:** February 08, 2006, 12:43:42 am »

Should we not post if it's blatantly obvious?

Sidoh · « **Reply #5 on:** February 08, 2006, 12:44:32 am »

Quote from: Blaze on February 08, 2006, 12:43:12 am

[ROT13]
Gjb qbrfa'g rdhny bar..? V qba'g hackrefgnaq gur dhrfgvba irel jryy..
[/ROT13]

Of course two doesn't equal one, but I provided proof! What's wrong with the proof?

Quote from: Quik on February 08, 2006, 12:43:42 am

Should we not post if it's blatantly obvious?

Sure, go for it.

Nate · « **Reply #6 on:** February 08, 2006, 06:04:29 pm »

n zvahf o rdhnyf 0. Lbh pna abg qvivqr ol mreb. yvar frira

Sidoh · « **Reply #7 on:** February 08, 2006, 06:42:20 pm »

Quote from: Nate on February 08, 2006, 06:04:29 pm

n zvahf o rdhnyf 0. Lbh pna abg qvivqr ol mreb. yvar frira

It's a combination of the first and the second to the last lines. (a - b)/(a -b) in itself is just fine, but since a = b, it's illegal. Correct.

Chavo · « **Reply #8 on:** February 09, 2006, 02:59:23 am »

A friend of mine (a Math major if you couldn't guess) often uses this as his away message

Joe · « **Reply #9 on:** February 09, 2006, 06:22:43 am »

Two never equals one. =p

EDIT -
Read the ROT13's. Someone turn on the right to delete your own posts in this forum! =)

Sidoh · « **Reply #10 on:** February 09, 2006, 07:47:44 pm »

Quote from: Joe[e2] on February 09, 2006, 06:22:43 am

Two never equals one. =p

EDIT -
Read the ROT13's. Someone turn on the right to delete your own posts in this forum! =)

It's not intuitively obvious; that's why it makes a good away message. It even confused Lihao (foreign exchange student from China) who's already had two years of calculus.

Nate · « **Reply #11 on:** February 09, 2006, 07:58:20 pm »

Its really simple but its kinda like a visual illusion. Your so amazed that they could prove a=b to be false that its hard to find the error.

Sidoh · « **Reply #12 on:** February 09, 2006, 08:03:09 pm »

Quote from: Nate on February 09, 2006, 07:58:20 pm

Its really simple but its kinda like a visual illusion. Your so amazed that they could prove a=b to be false that its hard to find the error.

Of course it's simple. Most things are simple once you understand the answer. The term "complicated" (which is an acceptable antonym for "simple," I think) describes something beyond one's comprehension or is barely understandable. I don't think anyone here would have a problem understanding [a - b = 0] when [a = b]. It becomes simple / obvious after the connection between those two statements are made; until then, it is not intuitively obvious.

If your brain is run by any sort of logic, you'll realize that there's obviously something wrong with this system. If you're interested or at least persistent, it's a matter of minutes (or seconds, even) of re-reading the equations. The people who don't figure it out are the ones who decide it's impossible for them to understand.

Newby · « **Reply #13 on:** February 11, 2006, 12:53:23 am »

My mom got this her first try around. Damnit.

Sidoh · « **Reply #14 on:** February 11, 2006, 12:57:21 am »

Quote from: Newby on February 11, 2006, 12:53:23 am

My mom got this her first try around. Damnit.

Anyone who knows elementary properties of algebra and mathematics will if they don't give up easily.

GameSnake · « **Reply #15 on:** February 14, 2006, 12:54:17 am »

How can 2 = _B_ if 2 = 1?
B

Sidoh · « **Reply #16 on:** February 14, 2006, 12:56:46 am »

Quote from: GameSnake on February 14, 2006, 12:54:17 am

How can 2 = _B_ if 2 = 1?
B

What? ...

Every single operation there is mathematically legal except the last. You can't devide by zero.

GameSnake · « **Reply #17 on:** February 14, 2006, 06:30:45 pm »

Quote from: Sidoh on February 14, 2006, 12:56:46 am

Quote from: GameSnake on February 14, 2006, 12:54:17 am
How can 2 = _B_ if 2 = 1?
B

What? ...

Every single operation there is mathematically legal except the last. You can't devide by zero.

2 = B over B
2 = 1

I just thought something was wrong there so I took a stab at it, I see it's solved now, though.

Super_X · « **Reply #18 on:** February 15, 2006, 03:20:26 pm »

B devided by B = 1.

So, that's how.

d&q · « **Reply #19 on:** February 15, 2006, 08:48:51 pm »

In my opinion, it's blatantly obvious. Just substitute b for a, and seeing (blank)/a-b, one would instantly realize its a division by zero error.

Sidoh · « **Reply #20 on:** February 15, 2006, 09:33:37 pm »

Quote from: Deuce on February 15, 2006, 08:48:51 pm

In my opinion, it's blatantly obvious. Just substitute b for a, and seeing (blank)/a-b, one would instantly realize its a division by zero error.

As I've reiterated several times already, I think it is obvious too. However, it is not intuitively obvious. Algebraically, every single step is legal except the last. Even then, it's legal until you're able to tie in previous knowledge and recognize that you're dividing by zero.

Joe · « **Reply #21 on:** February 16, 2006, 01:50:36 pm »

V'z abg dhvgr fher vs gur nafjre jnf cbfgrq lrg, fb V thrff V'yy cbfg vg!

Vs N=O, gura N-O = 0, naq N-O/N-O = 0/0, juvpu vf qvivfvba ol mreb, juvpu vf jebat.

deadly7 · « **Reply #22 on:** February 16, 2006, 04:44:56 pm »

Quote from: Joe[e2] on February 16, 2006, 01:50:36 pm

V'z abg dhvgr fher vs gur nafjre jnf cbfgrq lrg, fb V thrff V'yy cbfg vg!

Vs N=O, gura N-O = 0, naq N-O/N-O = 0/0, juvpu vf qvivfvba ol mreb, juvpu vf jebat.

Just because you're retarded to put that into ROT13, I'm not going to even bother translating.

Sidoh · « **Reply #23 on:** February 16, 2006, 06:35:00 pm »

Quote from: Joe[e2] on February 16, 2006, 01:50:36 pm

V'z abg dhvgr fher vs gur nafjre jnf cbfgrq lrg, fb V thrff V'yy cbfg vg!

Vs N=O, gura N-O = 0, naq N-O/N-O = 0/0, juvpu vf qvivfvba ol mreb, juvpu vf jebat.

Just post it normally. I only recommend using ROT-13 on riddles that aren't mathematically oriented. It's easy to pull the answer out of there.

Not only is division by zero wrong, it is mathematically illegal.

Feanor · « **Reply #24 on:** March 28, 2006, 01:13:03 pm »

If A = B then A - B = 0

And you can not divide by zero (Only Feanor can divide by zero).

I see that it has already been solved though

News:

Author Topic: What's wrong here? (Read 7818 times)