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Author Topic: What's wrong here?  (Read 7762 times)

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Offline GameSnake

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Re: What's wrong here?
« Reply #15 on: February 14, 2006, 12:54:17 am »
How can 2 = _B_ if 2 = 1?
                       B
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Offline Sidoh

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Re: What's wrong here?
« Reply #16 on: February 14, 2006, 12:56:46 am »
Quote from: GameSnake on February 14, 2006, 12:54:17 am
How can 2 = _B_ if 2 = 1?
                       B

What? ...

Every single operation there is mathematically legal except the last.  You can't devide by zero.
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Offline GameSnake

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Re: What's wrong here?
« Reply #17 on: February 14, 2006, 06:30:45 pm »
Quote from: Sidoh on February 14, 2006, 12:56:46 am
Quote from: GameSnake on February 14, 2006, 12:54:17 am
How can 2 = _B_ if 2 = 1?
                       B

What? ...

Every single operation there is mathematically legal except the last.  You can't devide by zero.
2 = B over B
2 = 1

I just thought something was wrong there so I took a stab at it, I see it's solved now, though.
« Last Edit: February 14, 2006, 06:32:27 pm by GameSnake »
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Offline Super_X

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Re: What's wrong here?
« Reply #18 on: February 15, 2006, 03:20:26 pm »
B devided by B = 1.

So, that's how.
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Offline d&q

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Re: What's wrong here?
« Reply #19 on: February 15, 2006, 08:48:51 pm »
In my opinion, it's blatantly obvious. Just substitute b for a, and seeing (blank)/a-b, one would instantly realize its a division by zero error.
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Offline Sidoh

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Re: What's wrong here?
« Reply #20 on: February 15, 2006, 09:33:37 pm »
Quote from: Deuce on February 15, 2006, 08:48:51 pm
In my opinion, it's blatantly obvious. Just substitute b for a, and seeing (blank)/a-b, one would instantly realize its a division by zero error.

As I've reiterated several times already, I think it is obvious too.  However, it is not intuitively obvious.  Algebraically, every single step is legal except the last.  Even then, it's legal until you're able to tie in previous knowledge and recognize that you're dividing by zero.
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Offline Joe

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Re: What's wrong here?
« Reply #21 on: February 16, 2006, 01:50:36 pm »
V'z abg dhvgr fher vs gur nafjre jnf cbfgrq lrg, fb V thrff V'yy cbfg vg!

Vs N=O, gura N-O = 0, naq N-O/N-O = 0/0, juvpu vf qvivfvba ol mreb, juvpu vf jebat.
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I'd personally do as Joe suggests

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You might be right about that, Joe.

Offline deadly7

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Re: What's wrong here?
« Reply #22 on: February 16, 2006, 04:44:56 pm »
Quote from: Joe[e2] on February 16, 2006, 01:50:36 pm
V'z abg dhvgr fher vs gur nafjre jnf cbfgrq lrg, fb V thrff V'yy cbfg vg!

Vs N=O, gura N-O = 0, naq N-O/N-O = 0/0, juvpu vf qvivfvba ol mreb, juvpu vf jebat.
Just because you're retarded to put that into ROT13, I'm not going to even bother translating.
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Offline Sidoh

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Re: What's wrong here?
« Reply #23 on: February 16, 2006, 06:35:00 pm »
Quote from: Joe[e2] on February 16, 2006, 01:50:36 pm
V'z abg dhvgr fher vs gur nafjre jnf cbfgrq lrg, fb V thrff V'yy cbfg vg!

Vs N=O, gura N-O = 0, naq N-O/N-O = 0/0, juvpu vf qvivfvba ol mreb, juvpu vf jebat.

Just post it normally.  I only recommend using ROT-13 on riddles that aren't mathematically oriented.  It's easy to pull the answer out of there.

Not only is division by zero wrong, it is mathematically illegal.
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Offline Feanor

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Re: What's wrong here?
« Reply #24 on: March 28, 2006, 01:13:03 pm »
If A = B then A - B = 0

And you can not divide by zero (Only Feanor can divide by zero).


I see that it has already been solved though :(
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