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More Math Problems (Trig Functions)
trust:
My MathType trial ran out, so bear with the formating...
Compute Exact Value (Radians, not decimals):
[Is there a way to do these problems without using the unit circle? I don't know how...]
1) arccos(-sqrt(2)/2)
2) arcsin(-1/2)
3) arctan(sqrt(3))
4) arcsin(sin(2pi/3))
5) cos[arccos(-0.7)]
6) csc[arctan(4/3)]
Find The Inverse Function:
y= 4cos(-1/2x)
Write the equation for a sine function with a period of 5pi and a phase shift of pi units to the left and a range of (1,9]
------
a) List the transformations required for y=cos(x) => y=-5cos(4x-2pi)+3 (I put it in the calculator but it's weird...it shrunk alot and stuff)
b) Transform points (using above equation (y=-5cos...) make a table):
(0,1)
(pi/2,0)
(pi,-1)
(3pi/2,0)
(2pi/1)
c) Find the reciprocal equation of y=-5cos(4x-2pi)+3
Find period, domain, range:
1) y=(1/3)cot(2x)
2) 3cos[4(x+pi)] (also find amplitude)
3) y=sec(1/4x)+2
Any help is appreciated, these are due tomorrow morning so if you can do any of them that'd be a great help.
Thanks in advance.
rabbit:
The inverse is defined as that which is multiplied by the original gives 1 (#4 and #5).
MyndFyre:
--- Quote from: OG Trust on April 03, 2006, 06:07:47 pm ---My MathType trial ran out, so bear with the formating...
Compute Exact Value (Radians, not decimals):
[Is there a way to do these problems without using the unit circle? I don't know how...]
--- End quote ---
Why would you do these w/o the unit circle?
--- Quote from: OG Trust on April 03, 2006, 06:07:47 pm ---Find The Inverse Function:
y= 4cos(-1/2x)
--- End quote ---
y/4 = cos(-1/2x) // is that (1/2)x or 1/(2x) ? assuming former.
arccos(y/4) = -1/2x // you should be able to finish it from here.
trust:
Yes, the former.
I'd do it w/o unit circle because I haven't memorized it yet..I was supposed to like 2 months ago.
MyndFyre:
--- Quote from: OG Trust on April 03, 2006, 09:23:48 pm ---I'd do it w/o unit circle because I haven't memorized it yet..I was supposed to like 2 months ago.
--- End quote ---
Uh yeah do that, it's important and makes things FUCKING EASY. :) Thank you, that will be all.
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