Help! We're trapped in the computer, and the computer is trapped in 2008! Someone call the time police!
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huh? I'm considerably farther than you in the CompEn program and I have no idea what you are talking about.
Maybe, I have to take discrete to graduate, but since its not a prereq for any of my classes, I haven't yet.
View As Web PageDear Brandon, If you replace "prime" with "essential prime" in your message below, then you will be very close. The reason why I add the word essential is that you can get a prime implicant or implicate that you wind up not needing, beacuse the function has already been completely specified by other prime implicants. Here's an example that might help you.Consider the function:F(A,B,C,D) = sum minterms(3, 4, 5, 7, 9, 13, 14, 15). Note that, when you work it out, BD is a prime implicant. However, we won't use it in the minimal SOP expression, even though all the other terms have a bunch of 3-input AND gates! The reason for this is that we are forced to use those terms, for reasons that will become clear when you work through the example. Although we CAN use the term BD, we don't need it anymore, because we have covered all those 1's by that point anyway. There's one more caveat -- the solution is often not unique. So, when we have used up all the essential prime implicants, we often have to choose between a couple of equally good ways to mop up the rest of the K-map. As you work through the rest of the examples, you should see this occurring naturally. Hope this helps.
Alright, I worked out the problem and I got this:Essential Implicants: (not A)CD, (not A)B(not C), A(not C)D, ABCMinimal Sums: F(A,B,C,D) = ((not A)CD) + ((not A)B(not C)) + (A(not C)D)+ (ABC)Essential Implicates: (not A)CD, A(not C)D, (not A)B(not C), ABC Minimal Products: F(A,B,C,D) = ((not A)+C+D)((not A)+B+(not C))(A+(not C)+D)(A+B+C)Is that right?