(http://www.sidoh.org/~sidoh/2e1.gif)
For those of you that are more mathematically inclined (*cough* MyndFyre/iago): please don't reply until the answer's been posted. Thanks!
This should be in riddles, sorta.. Logic ~ Riddles, in a sense.
Since I know the answer (sidoh told me, I got semi close though) I can't post it.
[ROT13 (http://www.rot13.com)]
Gjb qbrfa'g rdhny bar..? V qba'g haqrefgnaq gur dhrfgvba irel jryy..
[/ROT13 (http://www.rot13.com)]
I actually considered that, but I figured it was okay in General. It does make more sense here, so I moved it. :)
Should we not post if it's blatantly obvious?
Quote from: Blaze on February 08, 2006, 12:43:12 AM
[ROT13 (http://www.rot13.com)]
Gjb qbrfa'g rdhny bar..? V qba'g hackrefgnaq gur dhrfgvba irel jryy..
[/ROT13 (http://www.rot13.com)]
Of course two doesn't equal one, but I provided proof! What's wrong with the proof?
Quote from: Quik on February 08, 2006, 12:43:42 AM
Should we not post if it's blatantly obvious?
Sure, go for it.
n zvahf o rdhnyf 0. Lbh pna abg qvivqr ol mreb. yvar frira
Quote from: Nate on February 08, 2006, 06:04:29 PM
n zvahf o rdhnyf 0. Lbh pna abg qvivqr ol mreb. yvar frira
It's a combination of the first and the second to the last lines. (a - b)/(a -b) in itself is just fine, but since a = b, it's illegal. Correct. :)
A friend of mine (a Math major if you couldn't guess) often uses this as his away message :)
Two never equals one. =p
EDIT -
Read the ROT13's. Someone turn on the right to delete your own posts in this forum! =)
Quote from: Joe[e2] on February 09, 2006, 06:22:43 AM
Two never equals one. =p
EDIT -
Read the ROT13's. Someone turn on the right to delete your own posts in this forum! =)
It's not intuitively obvious; that's why it makes a good away message. It even confused Lihao (foreign exchange student from China) who's already had two years of calculus.
Its really simple but its kinda like a visual illusion. Your so amazed that they could prove a=b to be false that its hard to find the error.
Quote from: Nate on February 09, 2006, 07:58:20 PM
Its really simple but its kinda like a visual illusion. Your so amazed that they could prove a=b to be false that its hard to find the error.
Of course it's simple. Most things are simple once you understand the answer. The term "complicated" (which is an acceptable antonym for "simple," I think) describes something beyond one's comprehension or is barely understandable. I don't think anyone here would have a problem understanding [a - b = 0] when [a = b]. It becomes simple / obvious after the connection between those two statements are made; until then, it is
not intuitively obvious.
If your brain is run by any sort of logic, you'll realize that there's obviously something wrong with this system. If you're interested or at least persistent, it's a matter of minutes (or seconds, even) of re-reading the equations. The people who don't figure it out are the ones who decide it's impossible for them to understand.
My mom got this her first try around. Damnit.
Quote from: Newby on February 11, 2006, 12:53:23 AM
My mom got this her first try around. Damnit.
Anyone who knows elementary properties of algebra and mathematics will if they don't give up easily. ;)
How can 2 = _B_ if 2 = 1?
B
Quote from: GameSnake on February 14, 2006, 12:54:17 AM
How can 2 = _B_ if 2 = 1?
B
What? ...
Every single operation there is mathematically legal except the last. You can't devide by zero.
Quote from: Sidoh on February 14, 2006, 12:56:46 AM
Quote from: GameSnake on February 14, 2006, 12:54:17 AM
How can 2 = _B_ if 2 = 1?
B
What? ...
Every single operation there is mathematically legal except the last. You can't devide by zero.
2 = B over B
2 = 1
I just thought something was wrong there so I took a stab at it, I see it's solved now, though.
B devided by B = 1.
So, that's how.
In my opinion, it's blatantly obvious. Just substitute b for a, and seeing (blank)/a-b, one would instantly realize its a division by zero error.
Quote from: Deuce on February 15, 2006, 08:48:51 PM
In my opinion, it's blatantly obvious. Just substitute b for a, and seeing (blank)/a-b, one would instantly realize its a division by zero error.
As I've reiterated several times already, I think it is obvious too. However, it is not
intuitively obvious. Algebraically, every single step is legal except the last. Even then, it's legal until you're able to tie in previous knowledge and recognize that you're dividing by zero.
V'z abg dhvgr fher vs gur nafjre jnf cbfgrq lrg, fb V thrff V'yy cbfg vg!
Vs N=O, gura N-O = 0, naq N-O/N-O = 0/0, juvpu vf qvivfvba ol mreb, juvpu vf jebat.
Quote from: Joe[e2] on February 16, 2006, 01:50:36 PM
V'z abg dhvgr fher vs gur nafjre jnf cbfgrq lrg, fb V thrff V'yy cbfg vg!
Vs N=O, gura N-O = 0, naq N-O/N-O = 0/0, juvpu vf qvivfvba ol mreb, juvpu vf jebat.
Just because you're retarded to put that into ROT13, I'm not going to even bother translating.
Quote from: Joe[e2] on February 16, 2006, 01:50:36 PM
V'z abg dhvgr fher vs gur nafjre jnf cbfgrq lrg, fb V thrff V'yy cbfg vg!
Vs N=O, gura N-O = 0, naq N-O/N-O = 0/0, juvpu vf qvivfvba ol mreb, juvpu vf jebat.
Just post it normally. I only recommend using ROT-13 on riddles that aren't mathematically oriented. It's easy to pull the answer out of there.
Not only is division by zero wrong, it is mathematically illegal.
If A = B then A - B = 0
And you can not divide by zero (Only Feanor can divide by zero).
I see that it has already been solved though :(