Trig Curriculum Review

[trust]

I'm not going to bother doing these in MathType. The deal is we have this assignment and if we do it it replaces a missing assignment (I have one missing assignment that's a large part of my grade, and I'm failing by like 4 points) so I have to do this no matter what. However, I want to get a good grade on it and I need to get it done by tomorrow morning. I took my exam today and it was hard, but this seems pretty easy (most of you math people could probably do this rather quickly. But for me it's rather extensive at 32 questions (I've done one))

1. Convert to radians: 25 degrees
2. Determine the angle coterminal to (-5pi/6)
3. A central angle [theta] of a circle with radius 9 in subtends an arc 20in. Find theta.
4. Give the exact value of csc(3pi/2) (radians)
5. Use function value, cot x = -1/4 to find the values of sin(-x) and csc(-x)
6. Find the point (x, y) on the unit circle that corresponds to the real number 8pi/3
7. A right triangle has an acute angle [theta] such that cot[theta]=15. Find cos[theta]
8. A 6ft man casts a shadow 14ft long. Find the angle of elevation of the sun.
9. Find the acute angle [theta] if cos[theta]=1/2
10. Determine the quadrant in which theta lies: sin[theta]<0, cos[theta]<0
11. Find the reference angle for theta = 17pi/15
12. Given sin[theta]=-4/7, 3pi/2 <= theta <= 2pi, find sec[theta]
13. Describe the transformation of f(x)=1+sin(2x-(pi/2))
14. Determine the amplitude and period of f(x) = 7cos(3x+pi)
15. omit
16. omit
17. omit
18. omit
19. A 40ft extension ladder leans against the side of a building and reaches a point 37ft above the ground. Find the angle of elevation the ladder makes with the ground.
20. Factor and simplify: ((cot^4)x)+((2cot^2)x)+1
21. Perform the subtraction and simplify: cscx/cosx  -  secx/cscx
22. Find all solutions in the interval [0,2pi]: 3tanx-3=0
23. Evaluate sin(105). (Use the fact that 105* = 60*+45*)
24. Simplify: sinx-(pi/6)
25. Given cos[theta]=-7/9 and tan[theta]<0, find sin2[theta]
26. Given a triangle with A=98*, a=27, b=16; find the area
27. Given a triangle with a=123, c=86, C=52*; find b
28. Given a triangle with b=120, c=142, B=78*; find a
29. A boat leaves port and sails 16mi at a bearing of S20*E. Another boat leaves the same port and sails 12mi at a bearing of S60*W. How far apart are the two boats at this point?
30. Determine the number of acres in a triangular parcel of land if the lengths of the sides measure 1702ft, 4021ft, and 4000ft. There are 43, 560 sqft in 1 acre.
31. A vector has an initial point (2, 5) and a terminal point (-1, 9). Find it's magnitude and direction.
32. Determine the relationship between the two given vectors. v=2i-3j and w=i+j


Now I don't expect anyone to do all of these but it'd be really helpful if you could do some of them. Thanks in advance

[trust]

oh yeah, work not required.

[d&q]

You can do alot of these with a graphing calculator.

[trust]

Hence "Work not required"

Thanks for your lovely input though.

[d&q]

I thought you posted these here because you found them too long and difficult to do. Evidently, I was mistaken. Sorry.

[Rule]

Start doing more of your own homework, and then you won't need so much help in the future.    :D

Nobody really wants to do your work for you, especially if you so obviously aren't interested in understanding the stuff (e.g. "work not required").

[deadly7]

1. (25pi)/180
6. ((2pi)/3, sin(120))
8. Wasn't sure which one.  heh.
13. Shifted up one, shifted to the right pi, period is 4pi
19. 67.6684 degrees
30. 78.350 acres

Since I did this for you, you must play ET with me.

[trust]

Start doing more of your own homework, and then you won't need so much help in the future.    :D

Nobody really wants to do your work for you, especially if you so obviously aren't interested in understanding the stuff (e.g. "work not required").

I'm more interested in passing versus learning something I'll never use again.

Deuce: I've done some of them already, I just have/had so much to do today when I came home from school I posted them hoping to cut down on some of the time. (My grandmother is flying in tomorrow and we're preparing and I had a doctors appointment and stuff)

deadly: Thanks, yeah, ET def. this summa.

[dark_drake]

2.  (7p)i/6 or 210 degrees
3.20/9 radians
4.-1
5. + and - 0.97014 and + and -1.030776406 I'm not totally sure on these.
7. Again, not totally sure because I don't have a graphing calculator. I'm just trying to use the basic windows calculator: 0.9977
9. 60 degrees
10. Quadrant III
11.(2pi)/15
12.sqrt(65)/7
14. Amplitude: 7, period: (2pi)/3

[dark_drake]

20.((csc^4)x)  I might have misread this one.
21.cotx
22.pi/4, 5pi/4
23.(sqrt(6) + sqrt(2)) / 4
25.-(56sqrt(2))/81
26.155.555209
27. Could be just be my crappy calculations, but I don't think this triangle is possible. c/sinC is not > a
28. With my calculations, it's not possible.  b/sinB is not > c
29.15.42690miles
31.magnitude: 5,  direction: 233.13* (I think....)
32. If by relationship, you mean angle, it's 78.69* (I think....)

I'm not so sure about my answers this time because I'm exhausted.

[trust]

word, thanks. You've really helped alot this semester.

[deadly7]

27. Could be just be my crappy calculations, but I don't think this triangle is possible. c/sinC is not > a

Well, C only has to be bigger if it's a right triangle, doesn't it?

[dark_drake]

27. Could be just be my crappy calculations, but I don't think this triangle is possible. c/sinC is not > a

Well, C only has to be bigger if it's a right triangle, doesn't it?

Using the law of Sines (a/sinA = b/sinB = c/sinC), the sides of the sines of their respective angles must be greater.  For example: Given a triangle with a=123, c=86, C=52*; find b.
First, I set out to find all the angles. I had C, so the next one I could get was A.
86/sin52 = 123/sinA
86/0.788=123/sinA
109.1355 = 123/sinA
109.1355 * sinA = 123
sinA = 123/109.1355
Now, to find the angle, you must take the inverse sine.  You cannot take the inverse sine of a number > 1.

At least, that was my reasoning.