News:

Happy New Year! Yes, the current one, not a previous one; this is a new post, we swear!

Main Menu

Horizontal Asymptote

Started by Ergot, May 18, 2006, 01:30:02 AM

Previous topic - Next topic

0 Members and 2 Guests are viewing this topic.

Ergot

Where is it when y = 3x / (x+3)^2 ?
Quote from: Newby on February 26, 2006, 12:16:58 AM
Who gives a damn? I fuck sheep all the time.
Quote from: rabbit on December 11, 2005, 01:05:35 PM
And yes, male both ends.  There are a couple lesbians that need a two-ended dildo...My router just refuses to wear a strap-on.
(05:55:03) JoE ThE oDD: omfg good job i got a boner thinkin bout them chinese bitches
(17:54:15) Sidoh: I love cosmetology

dark_drake

y = 0

At least if I remember correctly.
errr... something like that...

Ergot

Quote from: Newby on February 26, 2006, 12:16:58 AM
Who gives a damn? I fuck sheep all the time.
Quote from: rabbit on December 11, 2005, 01:05:35 PM
And yes, male both ends.  There are a couple lesbians that need a two-ended dildo...My router just refuses to wear a strap-on.
(05:55:03) JoE ThE oDD: omfg good job i got a boner thinkin bout them chinese bitches
(17:54:15) Sidoh: I love cosmetology

dark_drake

The limit as x approaches +infinity and -infinity is 0.
errr... something like that...

Sidoh

#4
Quote from: Ergot on May 18, 2006, 01:41:34 AM
Explain :( ?



Actually, there's a really easy way to do this problem (without graphing or anything).

Since the total powers of x (2) are greater in the denomonater than they are in the numerator, f(x) will approach 0 as x approaches infinity.  This is always the case with any function, no matter how big a constant on either may be.  Conversely, if the powers of x are larger in the numerator than in the demononator, f(x) will approach infinity.

dark_drake

Quote from: Sidoh on May 18, 2006, 01:50:23 AM
Quote from: Ergot on May 18, 2006, 01:41:34 AM
Explain :( ?
Since the total powers of x (2) are greater in the denomonater than they are in the numerator, f(x) will approach 0 as x approaches infinity.  This is always the case with any function, no matter how big a constant on either may be.  Conversely, if the powers of x are larger in the numerator than in the demononator, f(x) will approach infinity.
This is true; however, learning the limit thing is useful for when the powers are equal.  As always, I reccomend learning the basics and using shortcuts after growing comfortable with the basics.
errr... something like that...

Ergot

Thanks... I have a quiz on this tomorrow, hopefully he'll leave those types out...
drake... explain the basic to me? AFAIK, this will get me pretty far until I learn more in calc or w/e.
Quote from: Newby on February 26, 2006, 12:16:58 AM
Who gives a damn? I fuck sheep all the time.
Quote from: rabbit on December 11, 2005, 01:05:35 PM
And yes, male both ends.  There are a couple lesbians that need a two-ended dildo...My router just refuses to wear a strap-on.
(05:55:03) JoE ThE oDD: omfg good job i got a boner thinkin bout them chinese bitches
(17:54:15) Sidoh: I love cosmetology

dark_drake

#7
Quote from: Ergot on May 18, 2006, 02:01:07 AM
Thanks... I have a quiz on this tomorrow, hopefully he'll leave those types out...
drake... explain the basic to me? AFAIK, this will get me pretty far until I learn more in calc or w/e.
Just the limit as x approaches plus and minus infinity. How you do that, at least how I learned, is about like this:


Basically, you can't evaluate the limit of the function as x approaches infinity because when you plug infinity in, you get infnity/infinity, which is undefined.  So, you have to divide the numerator and denominator by the largest power of x.

Edit: This only works if the powers in the denominator are >= those in the numerator.  If the numerator's are greater, you're dealing with slant asymptotes.
errr... something like that...

Ergot

Quote from: Newby on February 26, 2006, 12:16:58 AM
Who gives a damn? I fuck sheep all the time.
Quote from: rabbit on December 11, 2005, 01:05:35 PM
And yes, male both ends.  There are a couple lesbians that need a two-ended dildo...My router just refuses to wear a strap-on.
(05:55:03) JoE ThE oDD: omfg good job i got a boner thinkin bout them chinese bitches
(17:54:15) Sidoh: I love cosmetology

rabbit

Or when it's undefined (IE: -3).

Ergot

Quote from: rabbit on May 19, 2006, 07:47:07 AM
Or when it's undefined (IE: -3).
That would be x = -3 or the vertical asymptote... that one is easy.
Quote from: Newby on February 26, 2006, 12:16:58 AM
Who gives a damn? I fuck sheep all the time.
Quote from: rabbit on December 11, 2005, 01:05:35 PM
And yes, male both ends.  There are a couple lesbians that need a two-ended dildo...My router just refuses to wear a strap-on.
(05:55:03) JoE ThE oDD: omfg good job i got a boner thinkin bout them chinese bitches
(17:54:15) Sidoh: I love cosmetology

rabbit

Fuck asymptotes, I'm done with high school!

MyndFyre

#12
Quote from: dark_drake on May 18, 2006, 02:06:20 AM
Quote from: Ergot on May 18, 2006, 02:01:07 AM
Thanks... I have a quiz on this tomorrow, hopefully he'll leave those types out...
drake... explain the basic to me? AFAIK, this will get me pretty far until I learn more in calc or w/e.
Just the limit as x approaches plus and minus infinity. How you do that, at least how I learned, is about like this:


Basically, you can't evaluate the limit of the function as x approaches infinity because when you plug infinity in, you get infnity/infinity, which is undefined.  So, you have to divide the numerator and denominator by the largest power of x.

Edit: This only works if the powers in the denominator are >= those in the numerator.  If the numerator's are greater, you're dealing with slant asymptotes.

Easier way to do that limit: L'Hospital's Rule. 



Really handy, because it can be applied several times.  For example, you want to find the limit of the following function:


So, as a good, easy mneumonic device:

1.) If the exponent of the numerator is greater, the function will have a limit of +infinity or -infinity.
2.) If the exponent of the denominator is greater, the function will have a limit of 0.  Series defined by this function will be convergent.
3.) If the exponents of the numerator and denominator are the same, the limit will be a constant of the numerator's greatest-power coefficient times the factorial of the power, divided by the denominator's greatest-power coefficient times the factorial of the power (in the example it was 6*5!/12*5!).  I believe that the series will be convergent, but I can't remember for sure.

Also, limits don't need to be taken to infinity.  They can be found at any point along the function.
Quote from: Joe on January 23, 2011, 11:47:54 PM
I have a programming folder, and I have nothing of value there

Running with Code has a new home!

Quote from: Rule on May 26, 2009, 02:02:12 PMOur species really annoys me.

Ergot

Uhh... I don't understand that :( I'm only in Algebra II.
Quote from: Newby on February 26, 2006, 12:16:58 AM
Who gives a damn? I fuck sheep all the time.
Quote from: rabbit on December 11, 2005, 01:05:35 PM
And yes, male both ends.  There are a couple lesbians that need a two-ended dildo...My router just refuses to wear a strap-on.
(05:55:03) JoE ThE oDD: omfg good job i got a boner thinkin bout them chinese bitches
(17:54:15) Sidoh: I love cosmetology

deadly7

What the hell do factorials have to do with this?  You have weird ways of doing things.. graphing takes about two seconds with a calculator and is way easier.
[17:42:21.609] <Ergot> Kutsuju you're girlfrieds pussy must be a 403 error for you
[17:42:25.585] <Ergot> FORBIDDEN

on IRC playing T&T++
<iago> He is unarmed
<Hitmen> he has no arms?!

on AIM with a drunk mythix:
(00:50:05) Mythix: Deadly
(00:50:11) Mythix: I'm going to fuck that red dot out of your head.
(00:50:15) Mythix: with my nine