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The Jesus Christ Problem

Started by Ender, November 23, 2006, 07:59:19 PM

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Ender

The customer favorite in the Joe's Nicotine-Enhanced Candy Store is the Jesus Christ ice cream bar. Jesus Christ Ice Cream Bars come in either packs of 7 or packs of 9.

Q1. What is the maximum number of Jesus Christ Ice Cream Bars that one cannot buy?
Q2. How many integer amounts of Jesus Christ Ice Cream Bars can one not buy?
Q3. Generalize your answer to Q1 to any situation where Jesus Christ Ice Cream bars come in either packs of a or packs of b, where a and b are integers.

You don't have to wait until you get solutions to all three to post.

rabbit


Ender


Nate

You worded something wrong because the first two are infinite.

Joe

Quote from: Nate on November 25, 2006, 10:40:25 PM
You worded something wrong because the first two are infinite.

Or he just said that at least one of them was incorrect, that being 3. It doesn't even make sense.
Quote from: Camel on June 09, 2009, 04:12:23 PMI'd personally do as Joe suggests

Quote from: AntiVirus on October 19, 2010, 02:36:52 PM
You might be right about that, Joe.


leet_muffin

The douchebag method:
Quote from: Trust on April 19, 2008, 02:58:00 AM
fuck allfo you i dont give a fuck ill fight everyone of you fuck that sbhit fuck you

d&q

The first two are infinite, one cannot buy an amount who's prime factorization does not include 9 or 7, which is an infinite set of numbers. I'm not sure about the third one though. Leet_muffin, how did you get 47?
The writ of the founders must endure.

leet_muffin

Try and add combinations of 9 and 7 to get 47. I couldn't. I didn't care to go any higher.
The douchebag method:
Quote from: Trust on April 19, 2008, 02:58:00 AM
fuck allfo you i dont give a fuck ill fight everyone of you fuck that sbhit fuck you

d&q

47 is a prime number, you shouldn't have bothered.  :P

[Edit]: Also, there is an infinitely high number of prime numbers if you care to know. I could look up the proof but I'm eating chicken right now and I'm too lazy.
The writ of the founders must endure.

leet_muffin

This has nothing to do with prime numbers...
The douchebag method:
Quote from: Trust on April 19, 2008, 02:58:00 AM
fuck allfo you i dont give a fuck ill fight everyone of you fuck that sbhit fuck you

d&q

#10
How does it not?

Quote from: leet_muffin on November 26, 2006, 08:04:45 PM
Try and add combinations of 9 and 7 to get 47.

Ex: 9 + 9 +9 + 7 + 7

That is equivalent to 3^3 + 7^2. Any combinations you are adding will be equivalent to some form 3^x + 7^x. Which is called prime factorization.

[Edit]: I misread it, my mistake.  :-\
The writ of the founders must endure.

leet_muffin

23 is a prime number. 7+7+9 = 23. I'm still not seeing how it involves prime numbers at all. Can you please explain?
The douchebag method:
Quote from: Trust on April 19, 2008, 02:58:00 AM
fuck allfo you i dont give a fuck ill fight everyone of you fuck that sbhit fuck you

Ender

Quote from: leet_muffin on November 26, 2006, 06:43:27 PM
1. 47?

You're right. Explain your answer though :P

Questions 2 and 3 still remain.

leet_muffin

#13
Uh, any number (edit:)higher than 47 can be created through different combinations of 9 and 7.

I'll work on 2 and 3 later, I be going afk.
The douchebag method:
Quote from: Trust on April 19, 2008, 02:58:00 AM
fuck allfo you i dont give a fuck ill fight everyone of you fuck that sbhit fuck you

Ender

Quote from: leet_muffin on December 02, 2006, 04:22:15 PM
Uh, any number of 47 can be created through different combinations of 9 and 7.

I'll work on 2 and 3 later, I be going afk.

You need to elucidate. 47 is the maximum number that cannot be created by any combination of 9 and 7.