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Started by iago, January 28, 2008, 09:50:39 AM

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iago

January 28, 2008, 09:50:39 AM


I don't know about you, but I sure as hell can't understand that!

warz

#1
January 28, 2008, 10:05:05 AM
wow, what a failure
http://www.chyea.org/ - web based markup debugger

nslay

#2
January 28, 2008, 10:33:42 AM
Code Select

if(you == understand.this){
make.a.girlfriend();
}
An adorable giant isopod!

Newby

#3
January 28, 2008, 10:41:24 AM
Looks like the stupid ads that appear on digg.
- Newby
http://www.x86labs.org

Quote[17:32:45] * xar sets mode: -oooooooooo algorithm ban chris cipher newby stdio TehUser tnarongi|away vursed warz
[17:32:54] * xar sets mode: +o newby
[17:32:58] <xar> new rule
[17:33:02] <xar> me and newby rule all

Quote from: Rule on June 30, 2008, 01:13:20 PM
Quote from: CrAz3D on June 30, 2008, 10:38:22 AM
I'd bet that you're currently bloated like a water ballon on a hot summer's day.

That analogy doesn't even make sense.  Why would a water balloon be especially bloated on a hot summer's day? For your sake, I hope there wasn't too much logic testing on your LSAT. 

iago

#4
January 28, 2008, 10:55:15 AM
Incidentally, some good replies from The Daily WTF...

Here's what the code maybe should look like:
Quoteif ( you.understand(this) ) { you.need("a girlfriend") }

And here's just a good response:
Quote

if (you == write_ads_like.this) {

    get.a.programming.book;

}

nslay

#5
January 28, 2008, 11:03:01 AM
Quote from: iago on January 28, 2008, 10:55:15 AM
Incidentally, some good replies from The Daily WTF...

Here's what the code maybe should look like:
Quoteif ( you.understand(this) ) { you.need("a girlfriend") }

And here's just a good response:
Quote

if (you == write_ads_like.this) {

    get.a.programming.book;

}

No, the original code works in C.  You can have a struct with a 'this' member.  Consequently, 'you' and 'this' are the same type.  But the code it executes as a result of the condition is dead code (e.g. the statement '5;' is dead code).

Code Select

struct lame {
  int this;
};

struct lame3 {
  int girlfriend;
}

struct lame2 {
  struct lame3 a;
};

int you;
struct lame understand;
struct lame2 get;

if ( you == understand.this ) {  /* Legal */
  get.a.girlfriend; /* Dead code - does nothing */
}


I know this is probably over analyzing an ad...
An adorable giant isopod!

iago

#6
January 28, 2008, 11:34:09 AM
Quote from: nslay on January 28, 2008, 11:03:01 AM
Quote from: iago on January 28, 2008, 10:55:15 AM
Incidentally, some good replies from The Daily WTF...

Here's what the code maybe should look like:
Quoteif ( you.understand(this) ) { you.need("a girlfriend") }

And here's just a good response:
Quote

if (you == write_ads_like.this) {

    get.a.programming.book;

}

No, the original code works in C.  You can have a struct with a 'this' member.  Consequently, 'you' and 'this' are the same type.  But the code it executes as a result of the condition is dead code (e.g. the statement '5;' is dead code).

Code Select

struct lame {
  int this;
};

struct lame3 {
  int girlfriend;
}

struct lame2 {
  struct lame3 a;
};

int you;
struct lame understand;
struct lame2 get;

if ( you == understand.this ) {  /* Legal */
  get.a.girlfriend; /* Dead code - does nothing */
}


I know this is probably over analyzing an ad...


Well, it *could* be valid code, but it still makes absolutely no sense. :P

Killer360

#7
January 28, 2008, 12:23:46 PM
No... it should be:

<html>
<body>
<h1>
STFU
</h1>
</body>
</html>
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