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Physics Problem

Started by Sidoh, October 05, 2006, 05:35:39 PM

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Sidoh

This is a seemingly easy problem.  I suspect I'm either fucking up something royally and overlooking some fundamental issue or the software used for homework is messed up somewhere.  Anyway, here's the problem.

You place a spring with negligible mass and a spring constant of vertically with one end on the floor.  You then drop a book with a mass of 1.20 kg onto it from a height of 0.500m above the top of the spring.  Find the maximum distance the spring will be compressed.

This is obviously a simple conservation of energy problem, but it keeps saying I'm wrong!  I'm using this relationship: , so the distance, according to this relationship, should be , which yields , but I'm clearly wrong! :(

Anyone have ideas?

Rule

#1
If you placed the book on the spring from a height of 0m, the spring would clearly compress, and your formula says it would not. 

Try mg/k + sqrt(2mgh/k)

Edit:
To find the position of the object at all times, solve the differential equation:
-md2y/dt2 +  ky - mg = 0
With the initial condition y(0) = 0
                                 v(0) = -sqrt(2gh)

(Guess e^(rt) as a solution, and use Euler's theorem)

Sidoh

Aha!

Ugh, I should have thought of that.

Thanks, Rule. :)

Nate

its right...8.85cm?  Atleast the answer sounds right.

Sidoh

Quote from: Nate on October 12, 2006, 12:07:49 AM
its right...8.85cm?  Atleast the answer sounds right.

Rule answered the question:

Quote from: Rule on October 05, 2006, 06:36:16 PM
If you placed the book on the spring from a height of 0m, the spring would clearly compress, and your formula says it would not. 

Nate

Thats cause you are treating height of the spring as 0, when its height of the spring.

Sidoh

Quote from: Nate on October 12, 2006, 01:10:48 AM
Thats cause you are treating height of the spring as 0, when its height of the spring.

Reference frames are hardly objective. :P