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Any hookah smokers? Or electrically inclined people...

Started by CrAz3D, November 20, 2006, 02:19:25 PM

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CrAz3D

http://en.wikipedia.org/wiki/Hookah

Mid eastern tobacco smoking device.
A lot smoother than cigarettes, but slightly better (I think)...not much.

Anyhow, friends smoke a lot & don't like lighting coals on their stove so we were thinkin...an electric coil thing.

Now, we're thinking use a battery (a large one I guess) & steel coil instead of the coal. 

SO, my question is what would be the best way to do that?  We need the steel coils to be red hot so it can smoke the sheesha (tobacco covered in molasses I believe).  Would we want to plug something into a wall socket & have a regulator of some sort or would a large battery work?



That's the bowl that the tobacco sits in, you set the coal on top of the tobacco (or on a plate/foil above the tobacco)

Sidoh

You'd need a decent amount of voltage to heat most metals to the point they're "red hot."  I'm not sure what the specific heat of steel is, but if you can find a somewhat heavy spring, I'm pretty sure it'd do the trick.  I don't know specifically how much current/potential you'd need to heat a coil like that, but I'm pretty sure you'd need to use a DC power source.

In any case, smoking is bad, mmmkay?

CrAz3D

Yeah, I was beginning to think heavier coil.

We'd like to try a battery, just so we can get portability out of it.  If not, we'll resort to a nice wall socket plug/cord/regulator setup I believe

Newby

- Newby
http://www.x86labs.org

Quote[17:32:45] * xar sets mode: -oooooooooo algorithm ban chris cipher newby stdio TehUser tnarongi|away vursed warz
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Quote from: Rule on June 30, 2008, 01:13:20 PM
Quote from: CrAz3D on June 30, 2008, 10:38:22 AM
I'd bet that you're currently bloated like a water ballon on a hot summer's day.

That analogy doesn't even make sense.  Why would a water balloon be especially bloated on a hot summer's day? For your sake, I hope there wasn't too much logic testing on your LSAT. 

Sidoh

Quote from: CrAz3D on November 20, 2006, 05:30:21 PM
Yeah, I was beginning to think heavier coil.

We'd like to try a battery, just so we can get portability out of it.  If not, we'll resort to a nice wall socket plug/cord/regulator setup I believe

A battery is probably your best bet anyway.  Try a car battery, but be careful not to kill yourselves.

I wish I could give advice with greater degrees of certainty, but I'm relatively uneducated in electricity.  Maybe after next semester...

rabbit

You should smoke cyanide instead of tobacco.  It has the same overall effect, only faster.

MyndFyre

Quote from: rabbit on November 20, 2006, 08:37:58 PM
You should smoke cyanide instead of tobacco.  It has the same overall effect, only faster.
LMFAO
Quote from: Joe on January 23, 2011, 11:47:54 PM
I have a programming folder, and I have nothing of value there

Running with Code has a new home!

Quote from: Rule on May 26, 2009, 02:02:12 PMOur species really annoys me.

CrAz3D

Quote from: Newby on November 20, 2006, 06:33:27 PM
The idea is to use a coal... as far as I know.
Yes, but you can use electric heaters too, you just need something hot enough to make the tobacco smoke

Chavo

If you have a decent voltage source and a good heating element it should work fine.

The equation for heat given off by a 'resistor' (any simple element that resists the flow of current) is just the Power equation P=IV.  You can rewrite it as P=V2/R where R is the resistance of your heating element and V is the Voltage across your resistor (not the voltage source).  You can find the resistance of your coil of wire by using R = pl/A where p = resistivity of the element (greek charactor rho), l is the length of your resistor (the length of the coil if it were stretched out straight), and the cross-sectional area of the wire (estimate it).

Rewriting,
P= V2*A / p*l     The resistivity constant of iron is 1.0×10-7.  I don't have a number for steel so I'm going to approximate it as iron.  For the benefit of this example, lets call the width of the wire 1mm which gives a radial area of 7.85×10-7 m2.  Let's again assume a realistic figure of .25m for the stretched out length of wire.  If you use a car battery, your Voltage is ~12V (the internal resistance is negligible).

P = 12V * 7.85×10-7 m2 / (1.0×10-7 * .25m) = 376.8 W.  At this power output, it would take about 16 seconds to boil one ounce of water (incorrectly assuming all the thermal power is transferred). I used water because I don't know what temperature you need the tobacco to be and 100 degrees Celsius is easy.  It takes about 6000 Joules of energy to boil an ounce of water (use Energy = Power * time in seconds for a close estimation).   In any case, I doubt someone using this device will want to use it only every 16 seconds (approximately). so for the estimations I gave, it doesn't look feasible.  However, you could mess around with that (perhaps find a better material) to get some numbers you like. 

CrAz3D

Quote from: unTactical on November 21, 2006, 11:21:05 AM
If you have a decent voltage source and a good heating element it should work fine.

*number crap*
Yeah, I just need more juice flowing I guess.